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Sounds

Pitch and Frequency
·         Pitch and Frequency
·         The Speed of Sound
·         The Human Ear
A sound wave, like any other wave, is introduced into a medium by a vibrating object. The vibrating object is the source of the disturbance that moves through the medium. The vibrating object that creates the disturbance could be the vocal cords of a person, the vibrating string and sound board of a guitar or violin, the vibrating tines of a tuning fork, or the vibrating diaphragm of a radio speaker. Regardless of what vibrating object is creating the sound wave, the particles of the medium through which the sound moves is vibrating in a back and forth motion at a given frequency. The frequency of a wave refers to how often the particles of the medium vibrate when a wave passes through the medium. The frequency of a wave is measured as the number of complete back-and-forth vibrations of a particle of the medium per unit of time. If a particle of air undergoes 1000 longitudinal vibrations in 2 seconds, then the frequency of the wave would be 500 vibrations per second. A commonly used unit for frequency is the Hertz (abbreviated Hz), where
1 Hertz = 1 vibration/second
As a sound wave moves through a medium, each particle of the medium vibrates at the same frequency. This is sensible since each particle vibrates due to the motion of its nearest neighbor. The first particle of the medium begins vibrating, at say 500 Hz, and begins to set the second particle into vibrational motion at the same frequency of 500 Hz. The second particle begins vibrating at 500 Hz and thus sets the third particle of the medium into vibrational motion at 500 Hz. The process continues throughout the medium; each particle vibrates at the same frequency. And of course the frequency at which each particle vibrates is the same as the frequency of the original source of the sound wave. Subsequently, a guitar string vibrating at 500 Hz will set the air particles in the room vibrating at the same frequency of 500 Hz, which carries a sound signal to the ear of a listener, which is detected as a 500 Hz sound wave.


 
The back-and-forth vibrational motion of the particles of the medium would not be the only observable phenomenon occurring at a given frequency. Since a sound wave is a pressure wave, a detector could be used to detect oscillations in pressure from a high pressure to a low pressure and back to a high pressure. As the compressions (high pressure) and rarefactions (low pressure) move through the medium, they would reach the detector at a given frequency. For example, a compression would reach the detector 500 times per second if the frequency of the wave were 500 Hz. Similarly, a rarefaction would reach the detector 500 times per second if the frequency of the wave were 500 Hz. The frequency of a sound wave not only refers to the number of back-and-forth vibrations of the particles per unit of time, but also refers to the number of compressions or rarefactions that pass a given point per unit of time. A detector could be used to detect the frequency of these pressure oscillations over a given period of time. The typical output provided by such a detector is a pressure-time plot as shown below.

Since a pressure-time plot shows the fluctuations in pressure over time, the period of the sound wave can be found by measuring the time between successive high pressure points (corresponding to the compressions) or the time between successive low pressure points (corresponding to the rarefactions). As discussed in an earlier unit, the frequency is simply the reciprocal of the period. For this reason, a sound wave with a high frequency would correspond to a pressure time plot with a small period - that is, a plot corresponding to a small amount of time between successive high pressure points. Conversely, a sound wave with a low frequency would correspond to a pressure time plot with a large period - that is, a plot corresponding to a large amount of time between successive high pressure points. The diagram below shows two pressure-time plots, one corresponding to a high frequency and the other to a low frequency.

 
Frequency, Pitch and Human Perception
The ears of a human (and other animals) are sensitive detectors capable of detecting the fluctuations in air pressure that impinge upon the eardrum. The mechanics of the ear's detection ability will be discussed later in this lesson. For now, it is sufficient to say that the human ear is capable of detecting sound waves with a wide range of frequencies, ranging between approximately 20 Hz to 20 000 Hz. Any sound with a frequency below the audible range of hearing (i.e., less than 20 Hz) is known as an infrasound and any sound with a frequency above the audible range of hearing (i.e., more than 20 000 Hz) is known as an ultrasound. Humans are not alone in their ability to detect a wide range of frequencies. Dogs can detect frequencies as low as approximately 50 Hz and as high as 45 000 Hz. Cats can detect frequencies as low as approximately 45 Hz and as high as 85 000 Hz. Bats, being nocturnal creature, must rely on sound echolocation for navigation and hunting. Bats can detect frequencies as high as 120 000 Hz. Dolphins can detect frequencies as high as 200 000 Hz. While dogs, cats, bats, and dolphins have an unusual ability to detect ultrasound, an elephant possesses the unusual ability to detect infrasound, having an audible range from approximately 5 Hz to approximately 10 000 Hz.
 
The sensation of a frequency is commonly referred to as the pitch of a sound. A high pitch sound corresponds to a high frequency sound wave and a low pitch sound corresponds to a low frequency sound wave. Amazingly, many people, especially those who have been musically trained, are capable of detecting a difference in frequency between two separate sounds that is as little as 2 Hz. When two sounds with a frequency difference of greater than 7 Hz are played simultaneously, most people are capable of detecting the presence of a complex wave pattern resulting from the interference and superposition of the two sound waves. Certain sound waves when played (and heard) simultaneously will produce a particularly pleasant sensation when heard, are said to be consonant. Such sound waves form the basis of intervals in music. For example, any two sounds whose frequencies make a 2:1 ratio are said to be separated by an octave and result in a particularly pleasing sensation when heard. That is, two sound waves sound good when played together if one sound has twice the frequency of the other. Similarly two sounds with a frequency ratio of 5:4 are said to be separated by an interval of a third; such sound waves also sound good when played together. Examples of other sound wave intervals and their respective frequency ratios are listed in the table below.
Interval
Frequency Ratio
Examples
Octave
2:1
512 Hz and 256 Hz
Third
5:4
320 Hz and 256 Hz
Fourth
4:3
342 Hz and 256 Hz
Fifth
3:2
384 Hz and 256 Hz

The ability of humans to perceive pitch is associated with the frequency of the sound wave that impinges upon the ear. Because sound waves traveling through air are longitudinal waves that produce high- and low-pressure disturbances of the particles of the air at a given frequency, the ear has an ability to detect such frequencies and associate them with the pitch of the sound. But pitch is not the only property of a sound wave detectable by the human ear. In the next part of Lesson 2, we will investigate the ability of the ear to perceive the intensity of a sound wave.

Every musical note is associated with a unique frequency. The two widgets below allow you to investigate the relationship between a musical note and the associated frequency.




Check Your Understanding
1. Two musical notes that have a frequency ratio of 2:1 are said to be separated by an octave. A musical note that is separated by an octave from middle C (256 Hz) has a frequency of _____.
a. 128 Hz
b. 254 Hz
c. 258 Hz
d. 345 Hz
e. none of these

Sound Waves and Music - Lesson 2 - Sound Properties and Their Perception
Intensity and the Decibel Scale
·         Pitch and Frequency
·         Intensity and the Decibel Scale
·         The Speed of Sound
·         The Human Ear
Sound waves are introduced into a medium by the vibration of an object. For example, a vibrating guitar string forces surrounding air molecules to be compressed and expanded, creating a pressure disturbance consisting of an alternating pattern of compressions and rarefactions. The disturbance then travels from particle to particle through the medium, transporting energy as it moves. The energy that is carried by the disturbance was originally imparted to the medium by the vibrating string. The amount of energy that is transferred to the medium is dependent upon the amplitude of vibrations of the guitar string. If more energy is put into the plucking of the string (that is, more work is done to displace the string a greater amount from its rest position), then the string vibrates with a greater amplitude. The greater amplitude of vibration of the guitar string thus imparts more energy to the medium, causing air particles to be displaced a greater distance from their rest position. Subsequently, the amplitude of vibration of the particles of the medium is increased, corresponding to an increased amount of energy being carried by the particles. This relationship between energy and amplitudewas discussed in more detail in a previous unit.


 
Sound Intensity and Distance
The amount of energy that is transported past a given area of the medium per unit of time is known as the intensity of the sound wave. The greater the amplitude of vibrations of the particles of the medium, the greater the rate at which energy is transported through it, and the more intense that the sound wave is. Intensity is the energy/time/area; and since the energy/time ratio is equivalent to the quantity power, intensity is simply the power/area.

Typical units for expressing the intensity of a sound wave are Watts/meter2.
As a sound wave carries its energy through a two-dimensional or three-dimensional medium, the intensity of the sound wave decreases with increasing distance from the source. The decrease in intensity with increasing distance is explained by the fact that the wave is spreading out over a circular (2 dimensions) or spherical (3 dimensions) surface and thus the energy of the sound wave is being distributed over a greater surface area. The diagram at the right shows that the sound wave in a 2-dimensional medium is spreading out in space over a circular pattern. Since energy is conserved and the area through which this energy is transported is increasing, the intensity (being a quantity that is measured on a per areabasis) must decrease.

The mathematical relationship between intensity and distance is sometimes referred to as an 
inverse square relationship. The intensity varies inversely with the square of the distance from the source. So if the distance from the source is doubled (increased by a factor of 2), then the intensity is quartered (decreased by a factor of 4). Similarly, if the distance from the source is quadrupled, then the intensity is decreased by a factor of 16. Applied to the diagram at the right, the intensity at point B is one-fourth the intensity as point A and the intensity at point C is one-sixteenth the intensity at point A. Since the intensity-distance relationship is an inverse relationship, an increase in one quantity corresponds to a decrease in the other quantity. And since the intensity-distance relationship is an inverse square relationship, whatever factor by which the distance is increased, the intensity is decreased by a factor equal to the square of the distance change factor. The sample data in the table below illustrate the inverse square relationship between power and distance.
 
Distance
Intensity
1 m
160 units
2 m
40 units
3 m
17.8 units
4 m
10 units

 
The Threshold of Hearing and the Decibel Scale
Humans are equipped with very sensitive ears capable of detecting sound waves of extremely low intensity. The faintest sound that the typical human ear can detect has an intensity of 1*10-12 W/m2. This intensity corresponds to a pressure wave in which a compression of the particles of the medium increases the air pressure in that compressional region by a mere 0.3 billionth of an atmosphere. A sound with an intensity of 1*10-12 W/m2 corresponds to a sound that will displace particles of air by a mere one-billionth of a centimeter. The human ear can detect such a sound. WOW! This faintest sound that a human ear can detect is known as the threshold of hearing (TOH). The most intense sound that the ear can safely detect without suffering any physical damage is more than one billion times more intense than the threshold of hearing.
Since the range of intensities that the human ear can detect is so large, the scale that is frequently used by physicists to measure intensity is a scale based on powers of 10. This type of scale is sometimes referred to as a logarithmic scale. The scale for measuring intensity is the decibel scale. The threshold of hearing is assigned a sound level of 0 decibels (abbreviated 0 dB); this sound corresponds to an intensity of 1*10-12 W/m2. A sound that is 10 times more intense ( 1*10-11 W/m2) is assigned a sound level of 10 dB. A sound that is 10*10 or 100 times more intense (1*10-10 W/m2) is assigned a sound level of 20 db. A sound that is 10*10*10 or 1000 times more intense (1*10-9W/m2) is assigned a sound level of 30 db. A sound that is 10*10*10*10 or 10000 times more intense (1*10-8 W/m2) is assigned a sound level of 40 db. Observe that this scale is based on powers of 10. If one sound is 10x times more intense than another sound, then it has a sound level that is 10*x more decibels than the less intense sound. The table below lists some common sounds with an estimate of their intensity and decibel level.
Source
Intensity
Intensity Level
# of Times
Greater Than TOH
Threshold of Hearing (TOH)
1*10-12 W/m2
0 dB
100
Rustling Leaves
1*10-11 W/m2
10 dB
101
Whisper
1*10-10 W/m2
20 dB
102
Normal Conversation
1*10-6 W/m2
60 dB
106
Busy Street Traffic
1*10-5 W/m2
70 dB
107
Vacuum Cleaner
1*10-4 W/m2
80 dB
108
Large Orchestra
6.3*10-3 W/m2
98 dB
109.8
Walkman at Maximum Level
1*10-2 W/m2
100 dB
1010
Front Rows of Rock Concert
1*10-1 W/m2
110 dB
1011
Threshold of Pain
1*101 W/m2
130 dB
1013
Military Jet Takeoff
1*102 W/m2
140 dB
1014
Instant Perforation of Eardrum
1*104 W/m2
160 dB
1016


Investigate!
Knowing the intensity of a sound wave allows one to calculate the deciBel (dB) level of that sound. Use the DeciBel Calculator widget to determine the deciBel rating from any intensity in Watt/meter2. Enter intensities using scientific notation - for example, enter 5e-5 for 5.0x10-5.

 
While the intensity of a sound is a very objective quantity that can be measured with sensitive instrumentation, the loudness of a sound is more of a subjective response that will vary with a number of factors. The same sound will not be perceived to have the same loudness to all individuals. Age is one factor that affects the human ear's response to a sound. Quite obviously, your grandparents do not hear like they used to. The same intensity sound would not be perceived to have the same loudness to them as it would to you. Furthermore, two sounds with the same intensity but different frequencies will not be perceived to have the same loudness. Because of the human ear's tendency to amplify sounds having frequencies in the range from 1000 Hz to 5000 Hz, sounds with these intensities seem louder to the human ear. Despite the distinction between intensity and loudness, it is safe to state that the more intense sounds will be perceived to be the loudest sounds.

Investigate!
As mentioned in the previous paragraph, even the frequency will affect our perception of the loudness of a sound. For instance, a 100 Hz sound at 60 dB will not sound as loud as a 1000 Hz sound at 60 deciBel. Fletcher–Munson curves or equal loudness curves are often used to demonstrate the perceived loudness of a sound for a given frequency. Use the widget to investigate the effect of the frequency upon the perceived loudness and to view the equal loudness curves.


 



Check Your Understanding
1. A mosquito's buzz is often rated with a decibel rating of 40 dB. Normal conversation is often rated at 60 dB. How many times more intense is normal conversation compared to a mosquito's buzz?
a. 2
b. 20
c. 100
d. 200
e. 400
  
See Answer


2. The table at the right represents the decibel level for several sound sources. Use the table to make comparisons of the intensities of the following sounds.
How many times more intense is the front row of a Smashin' Pumpkins concert than ...
a. ... the 15th row of the same concert?
b. ... the average factory?
c. ... normal speech?
d. ... the library after school?
e. ... the sound that most humans can just barely hear?
  
See Answer



See Answer

Frequencies for equal-tempered scale, A4 = 440 Hz
Other tuning choices, A4 =
 440 

Speed of Sound = 345 m/s = 1130 ft/s = 770 miles/hr
More about Speed of Sound

("Middle C" is C
4 )


Note
Frequency (Hz)
Wavelength (cm)
C0
16.35
2109.89
 C#0/Db0 
17.32
1991.47
D0
18.35
1879.69
 D#0/Eb0 
19.45
1774.20
E0
20.60
1674.62
F0
21.83
1580.63
 F#0/Gb0 
23.12
1491.91
G0
24.50
1408.18
 G#0/Ab0 
25.96
1329.14
A0
27.50
1254.55
 A#0/Bb0 
29.14
1184.13
B0
30.87
1117.67
C1
32.70
1054.94
 C#1/Db1 
34.65
995.73
D1
36.71
939.85
 D#1/Eb1 
38.89
887.10
E1
41.20
837.31
F1
43.65
790.31
 F#1/Gb1 
46.25
745.96
G1
49.00
704.09
 G#1/Ab1 
51.91
664.57
A1
55.00
627.27
 A#1/Bb1 
58.27
592.07
B1
61.74
558.84
C2
65.41
527.47
 C#2/Db2 
69.30
497.87
D2
73.42
469.92
 D#2/Eb2 
77.78
443.55
E2
82.41
418.65
F2
87.31
395.16
 F#2/Gb2 
92.50
372.98
G2
98.00
352.04
 G#2/Ab2 
103.83
332.29
A2
110.00
313.64
 A#2/Bb2 
116.54
296.03
B2
123.47
279.42
C3
130.81
263.74
 C#3/Db3 
138.59
248.93
D3
146.83
234.96
 D#3/Eb3 
155.56
221.77
E3
164.81
209.33
F3
174.61
197.58
 F#3/Gb3 
185.00
186.49
G3
196.00
176.02
 G#3/Ab3 
207.65
166.14
A3
220.00
156.82
 A#3/Bb3 
233.08
148.02
B3
246.94
139.71
C4
261.63
131.87
 C#4/Db4 
277.18
124.47
D4
293.66
117.48
 D#4/Eb4 
311.13
110.89
E4
329.63
104.66
F4
349.23
98.79
 F#4/Gb4 
369.99
93.24
G4
392.00
88.01
 G#4/Ab4 
415.30
83.07
A4
440.00
78.41
 A#4/Bb4 
466.16
74.01
B4
493.88
69.85
C5
523.25
65.93
 C#5/Db5 
554.37
62.23
D5
587.33
58.74
 D#5/Eb5 
622.25
55.44
E5
659.25
52.33
F5
698.46
49.39
 F#5/Gb5 
739.99
46.62
G5
783.99
44.01
 G#5/Ab5 
830.61
41.54
A5
880.00
39.20
 A#5/Bb5 
932.33
37.00
B5
987.77
34.93
C6
1046.50
32.97
 C#6/Db6 
1108.73
31.12
D6
1174.66
29.37
 D#6/Eb6 
1244.51
27.72
E6
1318.51
26.17
F6
1396.91
24.70
 F#6/Gb6 
1479.98
23.31
G6
1567.98
22.00
 G#6/Ab6 
1661.22
20.77
A6
1760.00
19.60
 A#6/Bb6 
1864.66
18.50
B6
1975.53
17.46
C7
2093.00
16.48
 C#7/Db7 
2217.46
15.56
D7
2349.32
14.69
 D#7/Eb7 
2489.02
13.86
E7
2637.02
13.08
F7
2793.83
12.35
 F#7/Gb7 
2959.96
11.66
G7
3135.96
11.00
 G#7/Ab7 
3322.44
10.38
A7
3520.00
9.80
 A#7/Bb7 
3729.31
9.25
B7
3951.07
8.73
C8
4186.01
8.24
 C#8/Db8 
4434.92
7.78
D8
4698.63
7.34
 D#8/Eb8 
4978.03
6.93
E8
5274.04
6.54
F8
5587.65
6.17
 F#8/Gb8 
5919.91
5.83
G8
6271.93
5.50
 G#8/Ab8 
6644.88
5.19
A8
7040.00
4.90
 A#8/Bb8 
7458.62
4.63
B8
7902.13
4.37

(To convert lengths in cm to inches, divide by 2.54)





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